1.以文本的方式读取出xml内容

2.如果xml加载文本失败，替换掉乱码的内容

private static void loadxml(XmlDocument doc, string str){try{doc.LoadXml(str);}catch (System.Xml.XmlException ex){long count = 1;int position = 0;while (count < ex.LineNumber && (position = str.IndexOf('\n', position)) != -1){count++;position++;}string Newstr=str.Replace(str.Substring(position + ex.LinePosition - 1, 1), "");loadxml(doc, Newstr);}}